CSS Solved General Science and Ability (GSA) 2021 Paper by Sir Naveed | CSS 2021 Solved General Science and Ability (GSA) Paper | CSS 2021 GSA Solved Paper
Here is CSS Solved General Science and Ability (GSA) 2021 Paper by Sir Naveed. CSSPrepForum has requested him to solve the Math portion of the CSS 2021 GSA Paper. Nowadays, the GSA paper of CSS contains 40 marks, which plays a crucial role to score up to 90 in the paper – if covered and prepared thoroughly.
FEDERAL PUBLIC SERVICE COMMISSION
COMPETITIVE EXAMINATION – 2021
GENERAL KNOWLEDGE – I (GENERAL SCIENCE & ABILITY)
SOLUTION FOR PART-II (SECTION-B)
A man is now 3 times as old as his son. In ten (10) years’ time, the sum of their ages will be 76. How old was the man when his son was born?
This question was taken from the Age problem Unit in which we need to find out the age of the father when his son was born that depends upon the son age,
Age of Son = x
Age of Father = 3x (Man is 3 times as old as his son)
In 10 years’ time, the sum of their ages will be 76.
Now in 10 years’ time
Age of son = x+10
Age of Father = 3x+10
Age of Son + Age of Father = 76 (According to question statement)
(x+10) + (3x+10) = 76
(Now Solve to get the age of son)
x +10 + 3x + 10 = 76
4x + 20 = 76
4x = 76 -20
4x = 56
x = 14 (Age of Son in 10 years’ time)
Now put the son age to get the father age
Age of Father = 3x
= 42 (Age of Father in 10 years’ time)
Now just subtract the son’s age from father’s age to get the answer.
Age of Father when his son was born = 42 -14 = 28 Years
So, the Father’s age was 28 years when his son was born.
How many tiles of 20cm2 will be required to have a footpath 1m wide carried around the outside of grassy plot 24m long and 14m broad?
This question was taken from the Geometry Unit, in which we need to find out the number of tiles for making the footpath 1 meter wide outside around the grassy plot.
According to question grassy plot area
We use the following formula to calculate the area,
Area = Length * Width
So So the area of the grassy plot
= 24 * 14
= 336 m2
Now we need find the total area of grassy plot with footpath
Now calculate the area with a footpath
Area = Length * Width
= 26 * 16
= 416 m2
Now subtract the area of the grassy plot from the area of the grassy plot with a footpath to get the area of a footpath.
= 416 m2 – 336 m2
= 80 m
Let’s convert the m2 to cm2
80 m2 = 800,000 cm2 (As 1 m2 = 10,000 cm2)
One tile = 20 cm2
Now divide the total area to find out the number of tiles;
Number of tiles = 800,000/20
Number of tiles = 40,000
Mr. Faheem has dinner with his family at a restaurant that offers a 10% discount on food. The marked price of the food that they order was Rs. 15000/- Given that there were service charges of 10% and GST is 17%, calculate the total amount of money he has to pay.
This question was taken from the Percentage Unit in which we required to find the total amount, Faheem has to Pay,
Marked price of food = 15,000
Discount @ 10 % = 1,500 (15,000 * 10 % = 1,500)
Now add Service Charges @ 10 % on discounted amount
= 13,500 * 10 %
|One thing that needs to remember that GST charged on a Marked Price / Principal Amount.|
Now calculate the GST @ 17 %
= 15,000 * 17 %
Now calculate the amount that he has to pay,
Food price after discount = 13,500
Services Charges = 1,350
GST = 2,550
Mr. Khawaja walked for 45 minutes at the rate of 3km/h and then ran for half an hour at a certain speed. At the end of that time, he was 6km away from the starting point. How fast did he run?
This question was taken from the Time and Distance Unit in which we need to calculate the speed of Mr. Khawaja running,
We used the following formula to solve this type of question,
Distance = Speed * Time
In given question, there are 2 part,
- He walked for 45 minutes at a speed of 3km/h. (Find distance covered)
- He runs at a certain speed for half-hour and covers a distance. (Find distance and speed)
So, calculate the distance according to first part by using the above formula,
Distance = Speed * Time
= 3 Km/h * 0.75 h
= 2.25 Km
We need to convert the minutes in hours = 45/60 = 0.75 hour
So in the first 45 minutes, he covers 2.25 km.
Now find the distance cover by him by running as his total covered distance is 6 km.
Distance covered by running = Total distance covered – Distance covered by Walked
= 6 – 2.25
= 3.75 km
As you calculate
Distance = 3.75 km
Time = half hour = 0.5 hours (30min/60 = 0.50)
Solve the 2 part to find the speed of his running,
Distance = Speed * Time
𝑆𝑝𝑒𝑒𝑑 = 𝐷𝑖𝑠𝑡𝑎𝑛𝑐𝑒 / 𝑇𝑖𝑚𝑒
Speed = 3.75 / 0.5
Speed = 7.5 Km/h
A child went 90 meters in the east then he turned right and went 20 meters. Subsequently, he turned right and after going 30 meters he reaches his uncles home. From there, he went 100 meters to his north. Determine How far he is from the starting point?
This question was taken from the Direction problem Unit in which we required to calculate the distance from the starting point;
According to the question statement
Point A is the Starting point of the child and point F is the ending and we need to find the distance from point A to F, for this first we find the distance between A to E and E to F,
AE = AB – EB (AB=90 and DC=EB=30)
= 90 m – 30 m = 60 m
EF = DF – EF
= 100 m – 20 m = 80 m (DF=100 and BC=DE=20)
Now According to Pythagoras Theorem
(AF)2 = (AE)2 + (EF)2
Put the value of AF and EF as calculated above
The average of 11 numbers is 63, that of first 6 numbers is 60, and that of last 6 numbers is 65, find the 6th number
Mr Raheel invested Rs 60,000 in an account that earns simple interest. at the end of five years, the investment is worth rs 85000. calculate the rate of simple interest per year.
Q.8 (a) & (b)
This question was taken from the Geometry Unit in which we required to calculate the area and perimeter of the given shape.
For calculating the area use following formula
This question was taken from the number series Unit in which we required to find the missing figures,
About the Author
Sir Ch. Naveed is a Chartered Accountant (C.A) and has years of Math, accounting, auditing, and taxation experience in Pakistan. He has been teaching ACCA, ICMA, C.A, PIPFA, FPSC, PPSC, NTS, PMA, PAF, CSS, and other entrance and competitive students for years. CSSPrepForum has requested him to conduct an online session to help thousands of competitive students of CSS and FPSC.
Anybody who is interested in getting Sir Ch. Naveed’s Online GSA Math Session, kindly email their interest @ the email address: email@example.com
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